United States presidential election in Georgia, 1840

The 1840 United States presidential election in Georgia took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose eleven representatives, or electors to the Electoral College, who voted for President and Vice President.

Georgia voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Georgia by a margin of 11.56%.

Results

United States presidential election in Georgia, 1840[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Whig William Henry Harrison of Ohio John Tyler of Virginia 40,339 55.78% 11 100.00%
Democratic Martin Van Buren of New York Richard M. Johnson of Kentucky 31,983 44.22% 0 0.00%
Total 72,322 100.00% 11 100.00%

References

  1. "1840 Presidential General Election Results - Georgia". U.S. Election Atlas. Retrieved 23 December 2013.
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