United States presidential election in Missouri, 1860
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This article describes the United States presidential election, 1860, in Missouri.
Voters chose nine representatives, or electors to the Electoral College, who voted for President and Vice President. Missouri voted for the Democratic candidate, Stephen A. Douglas.
| Presidential Candidate | Running Mate | Party | Electoral Vote (EV) | Popular Vote (PV) | |
|---|---|---|---|---|---|
| Stephen A. Douglas | Herschel Johnson | Democratic | 9[1] | 58,801 | 35.52% |
| John Bell | Edward Everett | Constitutional Union | 0 | 58,372 | 35.26% |
| John Breckenridge | Joseph Lane | Southern Democrat | 0 | 31,362 | 18.94% |
| Abraham Lincoln | Hannibal Hamlin | Republican | 0 | 17,028 | 10.28% |
Statewide winner in bold.
See also
References
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