Shelby County, Illinois

Shelby County, Illinois

Shelby County Courthouse
Map of Illinois highlighting Shelby County
Location in the state of Illinois
Map of the United States highlighting Illinois
Illinois's location in the U.S.
Founded 1827
Named for Isaac Shelby
Seat Shelbyville
Largest city Shelbyville
Area
  Total 768 sq mi (1,989 km2)
  Land 759 sq mi (1,966 km2)
  Water 9.5 sq mi (25 km2), 1.2%
Population
  (2010) 22,363
  Density 29/sq mi (11/km²)
Congressional district 15th
Time zone Central: UTC-6/-5
Website www.shelbycounty-il.com

Shelby County is a county located in the U.S. state of Illinois. According to the 2010 census, it had a population of 22,363.[1] Its county seat is Shelbyville.[2]

History

Shelby County was formed in 1827 out of Fayette County. It was named in honor of Isaac Shelby, Governor of Kentucky and participant in the American Revolutionary War.

  1. ^ White, Jesse. Origin and Evolution of Illinois Counties. State of Illinois, March 2010. [1]

Geography

According to the U.S. Census Bureau, the county has a total area of 768 square miles (1,990 km2), of which 759 square miles (1,970 km2) is land and 9.5 square miles (25 km2) (1.2%) is water.[3]

Climate and weather

Shelbyville, Illinois
Climate chart (explanation)
JFMAMJJASOND
 
 
2
 
 
34
19
 
 
1.9
 
 
41
24
 
 
3.3
 
 
52
33
 
 
3.7
 
 
65
43
 
 
4
 
 
75
53
 
 
4.1
 
 
83
62
 
 
4
 
 
87
66
 
 
3.3
 
 
85
63
 
 
3.1
 
 
80
56
 
 
3.1
 
 
68
45
 
 
3.9
 
 
52
35
 
 
3
 
 
39
24
Average max. and min. temperatures in °F
Precipitation totals in inches
Source: The Weather Channel[4]

In recent years, average temperatures in the county seat of Shelbyville have ranged from a low of 19 °F (−7 °C) in January to a high of 87 °F (31 °C) in July, although a record low of −26 °F (−32 °C) was recorded in January 1915 and a record high of 111 °F (44 °C) was recorded in July 1936. Average monthly precipitation ranged from 1.89 inches (48 mm) in February to 4.05 inches (103 mm) in June.[4]

Major highways

Adjacent counties

Demographics

Historical population
Census Pop.
18302,972
18406,659124.1%
18507,80717.2%
186014,61387.2%
187025,47674.3%
188030,27018.8%
189031,1913.0%
190032,1263.0%
191031,693−1.3%
192029,601−6.6%
193025,471−14.0%
194026,2903.2%
195024,434−7.1%
196023,404−4.2%
197022,589−3.5%
198023,9235.9%
199022,261−6.9%
200022,8932.8%
201022,363−2.3%
Est. 201422,048[5]−1.4%
U.S. Decennial Census[6]
1790-1960[7] 1900-1990[8]
1990-2000[9] 2010-2013[1]

As of the 2010 United States Census, there were 22,363 people, 9,216 households, and 6,376 families residing in the county.[10] The population density was 29.5 inhabitants per square mile (11.4/km2). There were 10,396 housing units at an average density of 13.7 per square mile (5.3/km2).[3] The racial makeup of the county was 98.6% white, 0.3% Asian, 0.2% American Indian, 0.2% black or African American, 0.2% from other races, and 0.6% from two or more races. Those of Hispanic or Latino origin made up 0.8% of the population.[10] In terms of ancestry, 25.5% were German, 9.9% were English, 9.8% were American, and 8.8% were Irish.[11]

Of the 9,216 households, 29.2% had children under the age of 18 living with them, 57.1% were married couples living together, 8.0% had a female householder with no husband present, 30.8% were non-families, and 27.1% of all households were made up of individuals. The average household size was 2.40 and the average family size was 2.90. The median age was 43.5 years.[10]

The median income for a household in the county was $44,627 and the median income for a family was $55,655. Males had a median income of $40,119 versus $27,860 for females. The per capita income for the county was $21,891. About 7.8% of families and 11.3% of the population were below the poverty line, including 16.7% of those under age 18 and 8.1% of those age 65 or over.[12]

Communities

Cities

Town

Villages

Unincorporated communities

Townships

Shelby County is divided into these townships:

See also

References

Coordinates: 39°23′N 88°49′W / 39.39°N 88.81°W / 39.39; -88.81

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