Hardin Township, Pike County, Illinois
| Hardin Township | |
|---|---|
| Township | |
 Location in Pike County | |
 Pike County's location in Illinois | |
| Country | United States |
| State | Illinois |
| County | Pike |
| Established | November 8, 1853 |
| Area | |
| • Total | 37.41 sq mi (96.9 km2) |
| • Land | 37.39 sq mi (96.8 km2) |
| • Water | 0.03 sq mi (0.08 km2) 0.08% |
| Population (2010) | |
| • Total | 212 |
| • Density | 5.7/sq mi (2.2/km2) |
| Time zone | CST (UTC-6) |
| • Summer (DST) | CDT (UTC-5) |
Hardin Township is located in Pike County, Illinois. As of the 2010 census, its population was 212 and it contained 105 housing units.[1]
Geography
According to the 2010 census, the township encompasses an area of 37.41 square miles (96.9 km2), of which 37.39 square miles (96.8 km2) (or 99.95%) is land and 0.03 square miles (0.078 km2) (or 0.08%) is water.[1]
References
- 1 2 "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Retrieved 2013-05-28.
External links
| |||||||||||||||||||||||||||||||||
Coordinates: 39°31′42″N 90°44′49″W / 39.52833°N 90.74694°W
This article is issued from Wikipedia - version of the Tuesday, December 03, 2013. The text is available under the Creative Commons Attribution/Share Alike but additional terms may apply for the media files.