Independence Township, Saline County, Illinois
| Independence Township | |
| Township | |
| Country | United States |
|---|---|
| State | Illinois |
| County | Saline |
| Elevation | 374 ft (114 m) |
| Coordinates | 37°38′19″N 88°32′43″W / 37.63861°N 88.54528°WCoordinates: 37°38′19″N 88°32′43″W / 37.63861°N 88.54528°W |
| Area | 37.37 sq mi (96.8 km2) |
| - land | 36.87 sq mi (95 km2) |
| - water | 0.5 sq mi (1 km2) |
| Population | 1,118 (2010) |
| Density | 30.3 / sq mi (11.7 / km2) |
| Settled | November 5, 1889 |
| Timezone | CST (UTC-6) |
| - summer (DST) | CDT (UTC-5) |
 Location in Saline County
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  Location of Independence Township in Illinois
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 Location of Illinois in the United States
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Independence Township is located in Saline County, Illinois. As of the 2010 census, its population was 1,118 and it contained 478 housing units.[1]
Geography
According to the 2010 census, the township has a total area of 37.37 square miles (96.8 km2), of which 36.87 square miles (95.5 km2) (or 98.66%) is land and 0.5 square miles (1.3 km2) (or 1.34%) is water.[1]
References
- 1 2 "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Retrieved 2013-05-28.
External links
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