Seward Township, Winnebago County, Illinois
Seward Township | |
---|---|
Township | |
Combined township building and fire station | |
Location in Winnebago County | |
Coordinates: 42°14′45″N 89°20′19″W / 42.24583°N 89.33861°WCoordinates: 42°14′45″N 89°20′19″W / 42.24583°N 89.33861°W | |
Country | United States |
State | Illinois |
County | Winnebago |
Established | November 6, 1849 |
Government | |
• Supervisor | Garelt S. Stahl |
Area | |
• Total | 35.82 sq mi (92.8 km2) |
• Land | 35.81 sq mi (92.7 km2) |
• Water | 0 sq mi (0 km2) 0% |
Elevation | 853 ft (260 m) |
Population (2010) | |
• Total | 917 |
• Density | 25.6/sq mi (9.9/km2) |
Time zone | CST (UTC-6) |
• Summer (DST) | CDT (UTC-5) |
[1][2] |
Seward Township is located in Winnebago County, Illinois. As of the 2010 census, its population was 917 and it contained 394 housing units.[3]
Geography
According to the 2010 census, the township has a total area of 35.82 square miles (92.8 km2), all land.[3]
References
- ↑ U.S. Geological Survey Geographic Names Information System: Township of Seward
- ↑ Illinois Regional Archives Depository System. "Name Index to Illinois Local Governments". Illinois State Archives. Illinois Secretary of State. Retrieved 19 September 2014.
- 1 2 "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Retrieved 2013-05-28.
External links
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