United States Senate election in Pennsylvania, 1826
The 1826 United States Senate election in Pennsylvania was held on December 12, 1826. Isaac D. Barnard was elected by the Pennsylvania General Assembly to the United States Senate.[1]
Results
The Pennsylvania General Assembly, consisting of the House of Representatives and the Senate, convened on December 12, 1826, to elect a Senator to serve the term beginning on March 4, 1827. Two ballots were recorded. The results of the second and final ballot of both houses combined are as follows:
State Legislature Results[1] | ||||
---|---|---|---|---|
Party | Candidate | Votes | % | |
Democratic-Republican | Isaac D. Barnard | 108 | 81.20 | |
Federalist | Samuel D. Ingham | 11 | 8.27 | |
Federalist | Joseph Hemphill | 5 | 3.76 | |
Federalist | James Buchanan | 3 | 2.26 | |
Democratic-Republican | Thomas Sergeant | 1 | 0.75 | |
N/A | Not voting | 5 | 3.76 | |
Totals | 133 | 100.00% |
References
- 1 2 "U.S. Senate Election - 12 December 1826" (PDF). Wilkes University. Retrieved 21 December 2012.
External links
Preceded by 1820-21 |
Pennsylvania U.S. Senate election (Class I) 1826 |
Succeeded by 1831 |
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