United States presidential election in Pennsylvania, 1940

United States presidential election in Pennsylvania, 1940
Pennsylvania
November 5, 1940

 
Nominee Franklin D. Roosevelt Wendell Willkie
Party Democratic Republican
Home state New York Indiana
Running mate Henry A. Wallace Charles L. McNary
Electoral vote 36 0
Popular vote 2,171,035 1,889,848
Percentage 53.23% 46.33%

County results

President before election

Franklin D. Roosevelt
Democratic

Elected President

Franklin D. Roosevelt
Democratic

The 1940 United States presidential election in Pennsylvania took place on November 5, 1940 throughout the continuous 48 states. Voters chose 36 representatives, or electors to the Electoral College, who voted for President and Vice President.

Pennsylvania voted to give Democratic nominee, President Franklin D. Roosevelt an unprecedented third term, over the Republican nominee, corporate lawyer Wendell Willkie, a dark horse candidate that had never before run for a political office. Roosevelt won Pennsylvania by a margin of 6.9%.

Results

United States presidential [1]
Party Candidate Votes Percentage Electoral votes
Democratic Franklin D. Roosevelt 2,171,035 53.23% 36
Republican Wendell Willkie 1,889,848 46.33% 0
Socialist Norman Thomas 10,967 0.27% 0
Communist Earl Browder 4,519 0.11% 0
Industrial Government John Aiken 1,518 0.04% 0
Write-ins Write-ins 827 0.02% 0

References

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