United States presidential election in Pennsylvania, 1884

Main article: United States presidential election, 1884

November 4, 1884



Nominee	James G. Blaine	Grover Cleveland
Party	Republican	Democratic
Home state	Maine	New York
Running mate	John A. Logan	Thomas A. Hendricks
Electoral vote	30	0
Popular vote	478,804	392,785
Percentage	52.97%	43.46%

President before election

Chester A. Arthur
Republican

Elected President

Grover Cleveland
Democratic

Elections in Pennsylvania

Federal government

Presidential elections
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House of Representatives elections
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State government

Gubernatorial elections
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Elections by year

State elections
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Philadelphia

Mayoral elections
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Pittsburgh

Mayoral elections
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Lancaster

Mayoral elections
2009

The 1884 United States presidential election in Pennsylvania took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose 30 representatives, or electors to the Electoral College, who voted for President and Vice President.

Pennsylvania voted for the Republican nominee, James G. Blaine, over the Democratic nominee, Grover Cleveland. Blaine won Pennsylvania by a margin of 9.51%.

Results

United States presidential election in Pennsylvania, 1884^[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Republican	James G. Blaine	478,804	52.97%	30
	Democratic	Grover Cleveland	392,785	43.46%	0
	Greenback Labor	Benjamin Butler	16,992	1.88%	0
	Prohibition	John St. John	15,283	1.69%	0
Totals			903,864	100.0%	30

References

↑ "1884 Presidential General Election Results - Pennsylvania". U.S. Election Atlas. Retrieved 1 August 2012.

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