United States presidential election in Pennsylvania, 1860

Main article: United States presidential election, 1860

November 6, 1860



Nominee	Abraham Lincoln	John C. Breckinridge
Party	Republican	Southern Democratic
Home state	Illinois	Kentucky
Running mate	Hannibal Hamlin	Joseph Lane
Electoral vote	27	0
Popular vote	268,030	178,871
Percentage	56.26%	37.54%

President before election

James Buchanan
Democratic

Elected President

Abraham Lincoln
Republican

Elections in Pennsylvania

Federal government

Presidential elections
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United States Senate elections
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House of Representatives elections
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State government

Gubernatorial elections
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Lieutenant gubernatorial elections
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Attorney General elections
2000 2004 2008 · 2012
Auditor General elections
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State Treasurer elections
2000 2004 2008 2012
State Senate elections
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State House Elections
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Elections by year

State elections
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Philadelphia

Mayoral elections
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Pittsburgh

Mayoral elections
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Lancaster

Mayoral elections
2009

The 1860 United States presidential election in Pennsylvania took place on November 6, 1860, as part of the 1860 United States presidential election. Voters chose 27 representatives, or electors to the Electoral College, who voted for President and Vice President.

Pennsylvania voted for the Republican candidate, Abraham Lincoln, over the Southern Democratic candidate, John C. Breckinridge. Lincoln won Pennsylvania by a margin of 18.72%.

Results

United States presidential election in Pennsylvania, 1860^[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Republican	Abraham Lincoln	268,030	56.26%	27
	Southern Democratic	John C. Breckinridge	178,871	37.54%	0
	Democratic	Stephen A. Douglas	16,765	3.52%	0
	Constitutional Union	John Bell	12,776	2.68%	0
Totals			476,442	100.0%	27

References

↑ "1860 Presidential General Election Results - Pennsylvania". U.S. Election Atlas. Retrieved 3 August 2012.

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