United States presidential election in Idaho, 1992

United States presidential election in Idaho, 1992

November 3, 1992

Nominee George H.W. Bush Bill Clinton Ross Perot Party Republican Democratic Independent Home state Texas Arkansas Texas Running mate Dan Quayle Al Gore James Stockdale Electoral vote 4 0 0 Popular vote 202,645 137,013 130,395 Percentage 42.03% 28.42% 27.05%

County Results   Clinton—>70%   Clinton—60-70%   Clinton—50-60%   Clinton—40-50%   Bush—40-50%   Bush—50-60%   Bush—60-70%   Bush—>70%   Perot—40-50%

President before election George H. W. Bush Republican Elected President Bill Clinton Democratic

The 1992 United States presidential election in Idaho took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.

Idaho was won by incumbent President George H.W. Bush (R-Texas) with 42.03% of the popular vote over Governor Bill Clinton (D-Arkansas) with 28.42%. Businessman Ross Perot (I-Texas) finished in a close third with 27.05% of the popular vote.^[1] Clinton ultimately won the national vote, defeating both incumbent President Bush and Perot.^[2]

Results

United States presidential election in Idaho, 1992[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Republican	George H.W. Bush (incumbent)	202,645	42.03%	4
	Democratic	Bill Clinton	137,013	28.42%	0
	Independent	Ross Perot	130,395	27.05%	0
	America First	James "Bo" Gritz	10,281	2.13%	0
	Libertarian	Andre Marrou	1,167	0.24%	0
	New Alliance Party	Lenora Fulani	613	0.13%	0
Totals			482,114	100.0%	4

References

1. "1992 Presidential General Election Results - Idaho". U.S. Election Atlas. Retrieved 8 June 2012.
2. "1992 Presidential General Election Results". U.S. Election Atlas. Retrieved 8 June 2012.