United States presidential election in New Mexico, 1992

United States presidential election in New Mexico, 1992
New Mexico
November 3, 1992

 
Nominee Bill Clinton George H.W. Bush Ross Perot
Party Democratic Republican Independent
Home state Arkansas Texas Texas
Running mate Al Gore Dan Quayle James Stockdale
Electoral vote 5 0 0
Popular vote 261,617 212,824 91,895
Percentage 45.90% 37.34% 16.12%

County Results
  Clinton—60-70%
  Clinton—50-60%
  Clinton—40-50%
  Bush—40-50%
  Bush—50-60%

President before election

George H. W. Bush
Republican

Elected President

Bill Clinton
Democratic


The 1992 United States presidential election in New Mexico took place on November 3, 1992, as part of the 1992 United States presidential election. This was the 20th U.S. Presidential election that New Mexico participated in since 1912. New Mexico voters chose five electors to the Electoral College, who voted for President and Vice President.

New Mexico was won by Governor Bill Clinton (D-Arkansas) with 45.90% of the popular vote over incumbent President George H.W. Bush (R-Texas) with 37.34%. Businessman Ross Perot (I-Texas) finished in third with 16.12% of the popular vote.[1] Clinton ultimately won the national vote, defeating incumbent President Bush.[2]

Results

United States presidential election in New Mexico, 1992[1]
Party Candidate Votes Percentage Electoral votes
Democratic Bill Clinton 261,617 45.90% 5
Republican George H.W. Bush (incumbent) 212,824 37.34% 0
Independent Ross Perot 91,895 16.12% 0
Libertarian Andre Marrou 1,615 0.28% 0
U.S. Taxpayers' Howard Phillips 620 0.11% 0
Natural Law John Hagelin 562 0.10% 0
New Alliance Lenora Fulani 369 0.06% 0
Socialist Workers James Warren 183 0.03% 0
Workers World Gloria La Riva 181 0.03% 0
Prohibition Earl Dodge 120 0.02% 0
Totals 569,986 100.0% 5

References

  1. 1 2 "1992 Presidential General Election Results - New Mexico". U.S. Election Atlas. Retrieved 9 June 2012.
  2. "1992 Presidential General Election Results". U.S. Election Atlas. Retrieved 9 June 2012.
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