United States presidential election in Massachusetts, 1992

United States presidential election in Massachusetts, 1992

November 3, 1992

Nominee Bill Clinton George H.W. Bush Ross Perot Party Democratic Republican Independent Home state Arkansas Texas Texas Running mate Al Gore Dan Quayle James Stockdale Electoral vote 12 0 0 Popular vote 1,318,662 805,049 632,312 Percentage 47.54% 29.03% 22.80%

County Results   Clinton—60-70%   Clinton—50-60%   Clinton—40-50%   Clinton—<40%

President before election George H. W. Bush Republican Elected President Bill Clinton Democratic

The 1992 United States presidential election in Massachusetts took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose twelve representatives, or electors to the Electoral College, who voted for President and Vice President.

Massachusetts was won by Democratic Governor Bill Clinton of Arkansas with 47.54% of the popular vote over incumbent Republican President George H.W. Bush of Texas with 29.03%. Independent businessman Ross Perot of Texas finished in third with 22.80% of the popular vote.^[1] Clinton thus defeated Bush in the state with a margin of 18.52%.^[2]

Massachusetts weighed in as a solid 13% more Democratic than the national average in 1992.

Bush failed to carry a single county in the state, and his 29.03% of the vote was the smallest vote share a Republican presidential candidate had received in Massachusetts since 1964.

Clinton's decisive win in Massachusetts solidified the state's status in the modern era as a solid blue state. Massachusetts had been a Democratic-leaning state since 1928, and a Democratic stronghold since 1960. In 1972, Massachusetts was the only state in the nation to vote for Democrat George McGovern over Republican Richard Nixon in his 49-state landslide. However the state had trended Republican in the 1980s, with Ronald Reagan narrowly winning the state and George H.W. Bush taking a solid 45% and winning 3 counties in 1988. In 1992, Clinton not only carried the state by a double-digit margin, leaving Bush with less than 30% of the vote, but Clinton also swept every county in the state, as secular liberal New England rejected an increasingly Southern and conservative Republican Party dominated by Evangelical Christians. Since then, every Democratic presidential candidate that followed has carried the state by double-digit margins and won all 14 counties in Massachusetts.

Results

United States presidential election in Massachusetts, 1992[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	Bill Clinton	1,318,662	47.54%	12
	Republican	George H.W. Bush (incumbent)	805,049	29.03%	0
	Independent	Ross Perot	632,312	22.80%	0
	Libertarian	Andre Marrou	7,458	0.27%	0
	New Alliance	Lenora Fulani	3,172	0.11%	0
	Independent Voters (a)	Howard Phillips	2,217	0.08%	0
	Independent	Others (Write-In)	1,870	0.07%	0
	Natural Law	Dr. John Hagelin	1,812	0.07%	0
	Democrats for Economic Recovery	Lyndon LaRouche	1,007	0.04%	0
	Socialist	J. Quinn Brisben (Write-In)	13	<0.01%	0
	Prohibition	Earl Dodge (Write-In)	2	<0.01%	0
Totals			2,773,574	100.0%	12

(a) Howard Phillips was the candidate of the U.S. Taxpayers' Party nationally.

Results by Municipality

Results by town. Blue indicates towns carried by Bill Clinton, red indicates towns carried by George H.W. Bush, green indicates towns carried by Ross Perot.

References

1. "1992 Presidential General Election Results - Massachusetts". U.S. Election Atlas. Retrieved 8 June 2012.
2. "1992 Presidential General Election Results". U.S. Election Atlas. Retrieved 8 June 2012.