United States presidential election in Tennessee, 1992
United States presidential election in Tennessee, 1992
|
|
|
|
County Results
Clinton—>70%
Clinton—60-70%
Clinton—50-60%
Clinton—40-50%
Bush—40-50%
Bush—50-60%
Bush—60-70%
Bush—>70%
Perot—40-50% |
|
Elections in Tennessee |
|
|
|
|
The 1992 United States presidential election in Tennessee took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose eleven representatives, or electors to the Electoral College, who voted for President and Vice President.
Tennessee was won by Governor Bill Clinton (D-Arkansas) with 47.08% of the popular vote over incumbent President George H.W. Bush (R-Texas) with 42.43%. Businessman Ross Perot (I-Texas) finished in third with 10.09% of the popular vote.[1] Clinton ultimately won the national vote, defeating incumbent President Bush and Perot.[2]
Results
References
|
---|
| Candidates | | |
---|
| General articles | |
---|
| Local results | |
---|
| Other 1992 elections | |
---|
|
|
---|
| President | |
---|
| U.S. Senate | |
---|
| U.S. House | |
---|
| Governors | |
---|
| Mayors |
- Baton Rouge, LA
- San Diego, CA
|
---|
| States |
- Alabama
- Alaska
- American Samoa
- Arizona
- Arkansas
- California
- Colorado
- Connecticut
- Delaware
- Florida
- Georgia
- Guam
- Hawaii
- Idaho
- Illinois
- Indiana
- Iowa
- Kansas
- Kentucky
- Louisiana
- Maine
- Maryland
- Massachusetts
- Michigan
- Minnesota
- Mississippi
- Missouri
- Montana
- Nebraska
- Nevada
- New Hampshire
- New Jersey
- New Mexico
- New York
- North Carolina
- North Dakota
- Ohio
- Oklahoma
- Oregon
- Pennsylvania
- Puerto Rico
- Rhode Island
- South Carolina
- South Dakota
- Tennessee
- Texas
- United States Virgin Islands
- Utah
- Vermont
- Virginia
- Washington
- West Virginia
- Wisconsin
- Wyoming
|
---|
|