United States presidential election in South Dakota, 1992

United States presidential election in South Dakota, 1992

November 3, 1992

Nominee George H.W. Bush Bill Clinton Ross Perot Party Republican Democratic Independent Home state Texas Arkansas Texas Running mate Dan Quayle Al Gore James Stockdale Electoral vote 3 0 0 Popular vote 136,718 124,888 73,295 Percentage 40.66% 37.14% 21.80%

County Results   Clinton—>70%   Clinton—60-70%   Clinton—50-60%   Clinton—40-50%   Bush—40-50%   Bush—50-60%   Bush—60-70%   Bush—>70%   Perot—40-50%

President before election George H. W. Bush Republican Elected President Bill Clinton Democratic

The 1992 United States presidential election in South Dakota took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

South Dakota was won by incumbent President George H.W. Bush (R-Texas) with 40.66% of the popular vote over Governor Bill Clinton (D-Arkansas) with 37.14%. Businessman Ross Perot (I-Texas) finished in third with 21.80% of the popular vote.^[1] Clinton ultimately won the national vote, defeating incumbent President Bush and Perot.^[2]

Results

United States presidential election in South Dakota, 1992[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Republican	George H.W. Bush (incumbent)	136,718	40.66%	3
	Democratic	Bill Clinton	124,888	37.14%	0
	Independent	Ross Perot	73,295	21.80%	0
	Libertarian	Andre Marrou	814	0.24%	0
	Natural Law	Dr. John Hagelin	429	0.13%	0
	New Alliance Party	Lenora Fulani	110	0.03%	0
Totals			336,254	100.0%	3

References

1. "1992 Presidential General Election Results - South Dakota". U.S. Election Atlas. Retrieved 10 June 2012.
2. "1992 Presidential General Election Results". U.S. Election Atlas. Retrieved 10 June 2012.